1. Fungsi f ditentukan olehf(x) = ax + b. Jikaf(5) = 12
dan f(-3) = -4, maka nilai f(-2)+ f(2) adalah....
a. - 6
b. - 4.
d. 6
C. 4
dan f(-3) = -4, maka nilai f(-2)+ f(2) adalah....
a. - 6
b. - 4.
d. 6
C. 4
Fungsi
f(5) = 12 → 5a + b
f(-3) = -4 → -3a + b
Metode Eliminasi
5a + b = 12
-3a + b = -4
--------------------------- -
8a = 16
a = 16/8
a = 2
Metode Subtitusi
5a + b = 12
5(2) + b = 12
10 + b = 12
b = 12 - 10
b = 2
Rumus fungsi f(x) = 2x + 2
- Nilai f(-2) + f(2)
= (2(-2) + 2) + 2(2) + 2)
= (-4 + 2) (4 + 2)
= -2 + 6
= 4 (C)
Jawaban:
f(x) = ax + b
f(5) = 5a + b = 12
f(-3) = -3a + b = -4
-------------------------- -
5a + 3a = 12 + 4
8a = 16
a = 2
5a + b = 12
5(2) + b = 12
10 + b = 12
b = 12 - 10
b = 2
f(x) = 2x + 2
f(-2) = 2(-2) + 2
f(-2) = -4 + 2
f(-2) = -2
f(2) = 2(2) + 2
f(2) = 4 + 2
f(2) = 6
f(-2) + f(2)
= -2 + 6
= 4 (D)
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